Optimal. Leaf size=506 \[ -\frac{b e^2 \text{PolyLog}\left (2,1-\frac{2}{c \sqrt{x}+1}\right )}{d^3}+\frac{b e^2 \text{PolyLog}\left (2,1-\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}-\sqrt{e}\right )}\right )}{2 d^3}+\frac{b e^2 \text{PolyLog}\left (2,1-\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}+\sqrt{e}\right )}\right )}{2 d^3}-\frac{b e^2 \text{PolyLog}\left (2,-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{PolyLog}\left (2,c \sqrt{x}\right )}{d^3}+\frac{2 e^2 \log \left (\frac{2}{c \sqrt{x}+1}\right ) \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}-\sqrt{e}\right )}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}+\sqrt{e}\right )}\right )}{d^3}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{a e^2 \log (x)}{d^3}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}+\frac{b c e}{d^2 \sqrt{x}}-\frac{b c}{6 d x^{3/2}} \]
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Rubi [A] time = 0.872401, antiderivative size = 506, normalized size of antiderivative = 1., number of steps used = 24, number of rules used = 13, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.565, Rules used = {44, 1593, 5982, 5916, 325, 206, 5992, 5912, 6044, 5920, 2402, 2315, 2447} \[ -\frac{b e^2 \text{PolyLog}\left (2,1-\frac{2}{c \sqrt{x}+1}\right )}{d^3}+\frac{b e^2 \text{PolyLog}\left (2,1-\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}-\sqrt{e}\right )}\right )}{2 d^3}+\frac{b e^2 \text{PolyLog}\left (2,1-\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}+\sqrt{e}\right )}\right )}{2 d^3}-\frac{b e^2 \text{PolyLog}\left (2,-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{PolyLog}\left (2,c \sqrt{x}\right )}{d^3}+\frac{2 e^2 \log \left (\frac{2}{c \sqrt{x}+1}\right ) \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}-\sqrt{e}\right )}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{x}+1\right ) \left (c \sqrt{-d}+\sqrt{e}\right )}\right )}{d^3}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{a e^2 \log (x)}{d^3}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}+\frac{b c e}{d^2 \sqrt{x}}-\frac{b c}{6 d x^{3/2}} \]
Antiderivative was successfully verified.
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Rule 44
Rule 1593
Rule 5982
Rule 5916
Rule 325
Rule 206
Rule 5992
Rule 5912
Rule 6044
Rule 5920
Rule 2402
Rule 2315
Rule 2447
Rubi steps
\begin{align*} \int \frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{x^3 (d+e x)} \, dx &=2 \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{d x^5+e x^7} \, dx,x,\sqrt{x}\right )\\ &=2 \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{x^5 \left (d+e x^2\right )} \, dx,x,\sqrt{x}\right )\\ &=\frac{2 \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{x^5} \, dx,x,\sqrt{x}\right )}{d}-\frac{(2 e) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{x^3 \left (d+e x^2\right )} \, dx,x,\sqrt{x}\right )}{d}\\ &=-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x^4 \left (1-c^2 x^2\right )} \, dx,x,\sqrt{x}\right )}{2 d}-\frac{(2 e) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{x^3} \, dx,x,\sqrt{x}\right )}{d^2}+\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{x \left (d+e x^2\right )} \, dx,x,\sqrt{x}\right )}{d^2}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{\left (b c^3\right ) \operatorname{Subst}\left (\int \frac{1}{x^2 \left (1-c^2 x^2\right )} \, dx,x,\sqrt{x}\right )}{2 d}-\frac{(b c e) \operatorname{Subst}\left (\int \frac{1}{x^2 \left (1-c^2 x^2\right )} \, dx,x,\sqrt{x}\right )}{d^2}+\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \left (\frac{a+b \tanh ^{-1}(c x)}{d x}-\frac{e x \left (a+b \tanh ^{-1}(c x)\right )}{d \left (d+e x^2\right )}\right ) \, dx,x,\sqrt{x}\right )}{d^2}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c e}{d^2 \sqrt{x}}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{\left (b c^5\right ) \operatorname{Subst}\left (\int \frac{1}{1-c^2 x^2} \, dx,x,\sqrt{x}\right )}{2 d}-\frac{\left (b c^3 e\right ) \operatorname{Subst}\left (\int \frac{1}{1-c^2 x^2} \, dx,x,\sqrt{x}\right )}{d^2}+\frac{\left (2 e^2\right ) \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{x} \, dx,x,\sqrt{x}\right )}{d^3}-\frac{\left (2 e^3\right ) \operatorname{Subst}\left (\int \frac{x \left (a+b \tanh ^{-1}(c x)\right )}{d+e x^2} \, dx,x,\sqrt{x}\right )}{d^3}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c e}{d^2 \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{a e^2 \log (x)}{d^3}-\frac{b e^2 \text{Li}_2\left (-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{Li}_2\left (c \sqrt{x}\right )}{d^3}-\frac{\left (2 e^3\right ) \operatorname{Subst}\left (\int \left (-\frac{a+b \tanh ^{-1}(c x)}{2 \sqrt{e} \left (\sqrt{-d}-\sqrt{e} x\right )}+\frac{a+b \tanh ^{-1}(c x)}{2 \sqrt{e} \left (\sqrt{-d}+\sqrt{e} x\right )}\right ) \, dx,x,\sqrt{x}\right )}{d^3}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c e}{d^2 \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{a e^2 \log (x)}{d^3}-\frac{b e^2 \text{Li}_2\left (-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{Li}_2\left (c \sqrt{x}\right )}{d^3}+\frac{e^{5/2} \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{\sqrt{-d}-\sqrt{e} x} \, dx,x,\sqrt{x}\right )}{d^3}-\frac{e^{5/2} \operatorname{Subst}\left (\int \frac{a+b \tanh ^{-1}(c x)}{\sqrt{-d}+\sqrt{e} x} \, dx,x,\sqrt{x}\right )}{d^3}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c e}{d^2 \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{2 e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2}{1+c \sqrt{x}}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}-\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}+\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{d^3}+\frac{a e^2 \log (x)}{d^3}-\frac{b e^2 \text{Li}_2\left (-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{Li}_2\left (c \sqrt{x}\right )}{d^3}-2 \frac{\left (b c e^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1+c x}\right )}{1-c^2 x^2} \, dx,x,\sqrt{x}\right )}{d^3}+\frac{\left (b c e^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2 c \left (\sqrt{-d}-\sqrt{e} x\right )}{\left (c \sqrt{-d}-\sqrt{e}\right ) (1+c x)}\right )}{1-c^2 x^2} \, dx,x,\sqrt{x}\right )}{d^3}+\frac{\left (b c e^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2 c \left (\sqrt{-d}+\sqrt{e} x\right )}{\left (c \sqrt{-d}+\sqrt{e}\right ) (1+c x)}\right )}{1-c^2 x^2} \, dx,x,\sqrt{x}\right )}{d^3}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c e}{d^2 \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{2 e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2}{1+c \sqrt{x}}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}-\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}+\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{d^3}+\frac{a e^2 \log (x)}{d^3}+\frac{b e^2 \text{Li}_2\left (1-\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}-\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{2 d^3}+\frac{b e^2 \text{Li}_2\left (1-\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}+\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{2 d^3}-\frac{b e^2 \text{Li}_2\left (-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{Li}_2\left (c \sqrt{x}\right )}{d^3}-2 \frac{\left (b e^2\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+c \sqrt{x}}\right )}{d^3}\\ &=-\frac{b c}{6 d x^{3/2}}-\frac{b c^3}{2 d \sqrt{x}}+\frac{b c e}{d^2 \sqrt{x}}+\frac{b c^4 \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d}-\frac{b c^2 e \tanh ^{-1}\left (c \sqrt{x}\right )}{d^2}-\frac{a+b \tanh ^{-1}\left (c \sqrt{x}\right )}{2 d x^2}+\frac{e \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right )}{d^2 x}+\frac{2 e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2}{1+c \sqrt{x}}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}-\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{d^3}-\frac{e^2 \left (a+b \tanh ^{-1}\left (c \sqrt{x}\right )\right ) \log \left (\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}+\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{d^3}+\frac{a e^2 \log (x)}{d^3}-\frac{b e^2 \text{Li}_2\left (1-\frac{2}{1+c \sqrt{x}}\right )}{d^3}+\frac{b e^2 \text{Li}_2\left (1-\frac{2 c \left (\sqrt{-d}-\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}-\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{2 d^3}+\frac{b e^2 \text{Li}_2\left (1-\frac{2 c \left (\sqrt{-d}+\sqrt{e} \sqrt{x}\right )}{\left (c \sqrt{-d}+\sqrt{e}\right ) \left (1+c \sqrt{x}\right )}\right )}{2 d^3}-\frac{b e^2 \text{Li}_2\left (-c \sqrt{x}\right )}{d^3}+\frac{b e^2 \text{Li}_2\left (c \sqrt{x}\right )}{d^3}\\ \end{align*}
Mathematica [A] time = 2.67282, size = 394, normalized size = 0.78 \[ -\frac{b \left (3 e^2 x^2 \left (\text{PolyLog}\left (2,-\frac{\left (c^2 d+e\right ) e^{2 \tanh ^{-1}\left (c \sqrt{x}\right )}}{c^2 d-2 c \sqrt{-d} \sqrt{e}-e}\right )+\text{PolyLog}\left (2,-\frac{\left (c^2 d+e\right ) e^{2 \tanh ^{-1}\left (c \sqrt{x}\right )}}{c^2 d+2 c \sqrt{-d} \sqrt{e}-e}\right )+2 \tanh ^{-1}\left (c \sqrt{x}\right ) \left (\log \left (\frac{\left (c^2 d+e\right ) e^{2 \tanh ^{-1}\left (c \sqrt{x}\right )}}{c^2 d-2 c \sqrt{-d} \sqrt{e}-e}+1\right )+\log \left (\frac{\left (c^2 d+e\right ) e^{2 \tanh ^{-1}\left (c \sqrt{x}\right )}}{c^2 d+2 c \sqrt{-d} \sqrt{e}-e}+1\right )-\tanh ^{-1}\left (c \sqrt{x}\right )\right )\right )+6 e^2 x^2 \text{PolyLog}\left (2,e^{-2 \tanh ^{-1}\left (c \sqrt{x}\right )}\right )-3 \tanh ^{-1}\left (c \sqrt{x}\right ) \left (d \left (c^2 x-1\right ) \left (c^2 d x+d-2 e x\right )+2 e^2 x^2 \tanh ^{-1}\left (c \sqrt{x}\right )+4 e^2 x^2 \log \left (1-e^{-2 \tanh ^{-1}\left (c \sqrt{x}\right )}\right )\right )+c d \sqrt{x} \left (3 c^2 d x+d-6 e x\right )\right )+3 a d^2+6 a e^2 x^2 \log (d+e x)-6 a d e x-6 a e^2 x^2 \log (x)}{6 d^3 x^2} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.072, size = 741, normalized size = 1.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{2} \, a{\left (\frac{2 \, e^{2} \log \left (e x + d\right )}{d^{3}} - \frac{2 \, e^{2} \log \left (x\right )}{d^{3}} - \frac{2 \, e x - d}{d^{2} x^{2}}\right )} + b \int \frac{\log \left (c \sqrt{x} + 1\right )}{2 \,{\left (e x^{\frac{7}{2}} + d x^{\frac{5}{2}}\right )} \sqrt{x}}\,{d x} - b \int \frac{\log \left (-c \sqrt{x} + 1\right )}{2 \,{\left (e x^{\frac{7}{2}} + d x^{\frac{5}{2}}\right )} \sqrt{x}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \operatorname{artanh}\left (c \sqrt{x}\right ) + a}{e x^{4} + d x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \operatorname{artanh}\left (c \sqrt{x}\right ) + a}{{\left (e x + d\right )} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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